5y^4-7y^2+3/2=0

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Solution for 5y^4-7y^2+3/2=0 equation: 


y in (-oo:+oo)

5*y^4-(7*y^2)+3/2 = 0

5*y^4-7*y^2+3/2 = 0

t_1 = y^2

5*t_1^2-7*t_1^1+3/2 = 0

5*t_1^2-7*t_1+3/2 = 0

DELTA = (-7)^2-(3/2*4*5)

DELTA = 19

DELTA > 0

t_1 = (19^(1/2)+7)/(2*5) or t_1 = (7-19^(1/2))/(2*5)

t_1 = (19^(1/2)+7)/10 or t_1 = (7-19^(1/2))/10

t_1 = (7-19^(1/2))/10

y^2-((7-19^(1/2))/10) = 0

1*y^2 = (7-19^(1/2))/10 // : 1

y^2 = (7-19^(1/2))/10

y^2 = (7-19^(1/2))/10 // ^ 1/2

abs(y) = ((7-19^(1/2))^(1/2))/(10^(1/2))

y = ((7-19^(1/2))^(1/2))/(10^(1/2)) or y = -(((7-19^(1/2))^(1/2))/(10^(1/2)))

t_1 = (19^(1/2)+7)/10

y^2-((19^(1/2)+7)/10) = 0

1*y^2 = (19^(1/2)+7)/10 // : 1

y^2 = (19^(1/2)+7)/10

y^2 = (19^(1/2)+7)/10 // ^ 1/2

abs(y) = ((19^(1/2)+7)^(1/2))/(10^(1/2))

y = ((19^(1/2)+7)^(1/2))/(10^(1/2)) or y = -(((19^(1/2)+7)^(1/2))/(10^(1/2)))

y in { ((7-19^(1/2))^(1/2))/(10^(1/2)), -(((7-19^(1/2))^(1/2))/(10^(1/2))), ((19^(1/2)+7)^(1/2))/(10^(1/2)), -(((19^(1/2)+7)^(1/2))/(10^(1/2))) }

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